Pandas数据形状df.shape的实现_python

df.shape[1]

df.shape[0]   或者：len(df)

dataframe.shape()

import pandas as pd
 
df = pd.DataFrame([['liver','E',89,21,24,64],
                   ['Arry','C',36,37,37,57],
                   ['Ack','A',57,60,18,84],
                   ['Eorge','C',93,96,71,78],
                   ['Oah','D',65,49,61,86]
                  ], 
                   columns = ['name','team','Q1','Q2','Q3','Q4'])
 
df.shape
# (5, 6)
# 共5行6列(索引不算)
 
df.shape[0] # 5
df.shape[1] # 6
 
# Series只有一个值
s = pd.Series(['One','Two','Three'])
s.shape # (3,)
s.shape[0] # 3