Flutter 点击两次退出app的实现示例_Android

DateTime? lastPopTime;

onWillPop: () async {
  if (lastPopTime == null ||
      DateTime.now().difference(lastPopTime!) > Duration(seconds: 1)) {
    lastPopTime = DateTime.now();

    ToastUtils.showToast("再按一次退出");
    return Future.value(false);
  } else {
    lastPopTime = DateTime.now();
    // 退出app
    return Future.value(true);
  }
});

DateTime? lastPopTime;

onWillPop: () async {
  // webViewController?.goBack();
  // return Future.value(false);

  if (lastPopTime == null ||
      DateTime.now().difference(lastPopTime!) > Duration(seconds: 1)) {
    lastPopTime = DateTime.now();

    if (await webViewController?.canGoBack() == true) {
      await webViewController?.goBack();
    } else {
      ToastUtils.showToast("再按一次退出");
    }
    return Future.value(false);
  } else {
    lastPopTime = DateTime.now();
    // 退出app
    return Future.value(true);
    // await SystemChannels.platform.invokeMethod('SystemNavigator.pop');
  }
});