python中的元组与列表及元组的更改_python

>>> list=[1,2,3,4,5,6]
>>> list[0]=8
>>> list[6]=0
>>> list
[8, 2, 3, 4, 5, 6]

>>> len(list) #查看这个列表中有多少数据
6
>>> list.append(7) #在列表尾插入
>>> list
[8, 2, 3, 4, 5, 6, 7]
>>> len(list)
7
>>> list.insert(3,10)  #在列表任意位置插入数据，第一个参数表示索引，第二个参数表示插入的数据
>>> list
[8, 2, 3, 10, 4, 5, 6, 7]
>>> 

>>> tuple=(1,2,3,4)
>>> tuple
(1, 2, 3, 4)
>>> tuple[2]
3
>>> tuple[2]=8
Traceback (most recent call last):
  File "", line 1, in 
    tuple[2]=8
TypeError: 'tuple' object does not support item assignment

>>> t=(5,6,8,6)
>>> t+tuple
(5, 6, 8, 6, 1, 2, 3, 4)

 >>>t=(5631,103,"Finn","Bilous","Wanaka","1999-09-22")
 >>> print (t)
 (5631,103,"Finn","Bilous","Wanaka","1999-09-22")
 >>>lst = list(t)
 >>>print (lst)
 [5631,103,"Finn","Bilous","Wanaka","1999-09-22"]
 >>>lst[4] = 'LA'
 >>>t= tuple(lst)
 >>>print(t)
 (5631,103,"Finn","Bilous","LA","1999-09-22")

n=103
if n in t:#在元组t中查找103
    indexn = t.index(n)#查找值在元组中的索引值（从0开始算）
print(indexn)

n="Finn"
if n in t:
    indexn = t.index(n)
print(indexn)